Spørsmål # 94346

Svar:

#hat (PQR) = cos ^ (- 1) (27 / sqrt1235) #

Forklaring:

Vær to vektorer #vec (AB) # og #vec (AC) #:

#vec (AB) * vec (AC) = (AB) (AC) cos (hue (BAC)) #

# = (X_ (AB) X_ (AC)) + (V (co AB) V (co AC)) + (z_ (AB) z_ (AC)) #

Vi har:

# P = (1; 1; 1) #

#Q = (- 2, 2, 4) #

# R = (3, -4, 2) #

derfor

#vec (QP) = (x_P-x_Q; y_P-y_Q; z_P-z_Q) = (3, -1, -3) #

#vec (QR) = (x_R-x_Q; y_R-y_Q; z_R-z_Q) = (5, -6, -2) #

og

# (QP) = sqrt ((X_ (QP)) ^ 2 + (V (co QP)) ^ 2 + (z_ (QP)) ^ 2) = sqrt (9 + 1 + 9) = sqrt (19) #

# (QR) = sqrt ((X_ (QR)) ^ 2 + (V (co QR)) ^ 2 + (z_ (QR)) ^ 2) = sqrt (25 + 36 + 4) = sqrt (65) #

Derfor:

#vec (QP) * vec (QR) = sqrt19sqrt65cos (lue (PQR)) #

#=(3*5+(-1)(-6)+(-3)(-2))#

#rarr cos (hat (PQR)) = (15 + 6 + 6) / (sqrt19sqrt65) = 27 / sqrt1235 #

#rarr hat (PQR) = cos ^ (- 1) (27 / sqrt1235) #