Spørsmål # 7bd2c

Spørsmål # 7bd2c
Anonim

Svar:

Alternativ (A) aksepteres her.

Forklaring:

Gitt at, # Rarrsintheta + costheta = sqrt (2) cosalpha #

# Rarrcostheta * (1 / sqrt (2)) + sintheta * (1 / sqrt (2)) = cosalpha #

# Rarrcostheta * cos (pi / 4) + sintheta * sin (pi / 4) = cosalpha #

#rarrcos (theta-pi / 4) = cos (2npi + alfa) #

# Rarrtheta = 2npi + -a + pi / 4 #