Svar: # (x-2) #. Forklaring: Vi vet det, Utbytte = (Divisoren) (Quotienten) + Resten. Så, hvis Divisor Polynomial er #P (x) #, deretter, #:. (2x ^ 2-7x + 9) = (2x-3) * p (x) + 3 #. #:. 2x ^ 2-7x + 9-3 = (2x-3) * p (x) #, # dvs. 2x ^ 2-7x + 6 = (2x-3) * p (x) #. #:. p (x) = (2x ^ 2-7x + 6) / (2x-3) #, # = {(X-2) avbryter ((2x-3))} / avbryt ((2x-3)) #. # rArr "Divisor Poly. er" (x-2) #.