Hvordan skiller du y = ln ((x-1) / (x ^ 2 + 1))?

Svar:

# Dy / dx = (- x ^ 2 + 2x + 1) / ((x ^ 2 + 1) (x-1)) #

Forklaring:

# Y = ln ((x-1) / (x ^ 2 + 1)) #

# Y = ln (x-1) -lN (x ^ 2 + 1) #

Bruk kvotientregel for logaritmer

Nå skille mellom

# dy / dx = 1 / (x-1) -1 / (x ^ 2 + 1) * d / dx (x ^ 2 + 1)Bruk kjederegel

# Dy / dx = 1 / (x-1) -1 / (x ^ 2 + 1) * 2 x #

# dy / dx = 1 / (x-1) - (2x) / (x ^ 2 + 1) # Ta LCD-skjermen som ((x-1) (x ^ 2 + 1)

(x x 2) (x-1)) - ((2x) (x-1)) / ((x ^ 2 + 1) x-1))) #

# Dy / dx = (x ^ 2 + 1-2x ^ 2 + 2x) / ((x ^ 2 + 1) (x-1) #

# Dy / dx = (- x ^ 2 + 2x + 1) / ((x ^ 2 + 1) (x-1)) #